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the molar heat capacity of CDDO is 10cal at 1000K .The change in entropy associated with cooling of 32g ofCDDO vapour from 1000K to 100K at constant pressure will be

the molar heat capacity of CDDO is 10cal at 1000K .The change in entropy associated with cooling of 32g ofCDDO vapour from 1000K to 100K at constant pressure will be

Grade:12

2 Answers

Arun
25750 Points
6 years ago
Dear Prasad
 
Change in entropy =
 
Delta S = Cp ln (T2/T1) - R ln (P2/P1)
 
But P1 = P2 hence
 
Delta S = Cp ln (T2/T1) = 10 ln (100/1000)
 = - 10 ln 10 = - 10 * 2.303 log 10
= - 23.03 cal/degree
 
Regards
Arun (askIITians forum expert)
Rohit Sharma
63 Points
6 years ago
As we know,
Delta S = Cp ln(V2/v1) + R ln (p1/p2) 
as its constant pressure then,
Entropy = Cp ln(T2/T1)
You know all the values and can find the entropy easily,

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