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Grade 12th passPhysical Chemistry

The molal elevation constant of water is 0.51 Km–1 The boiling point of 0.1 molal aqueous NaCl solution is nearly :
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1. 100.05°C
2. 100.1°C
3. 100.2°C
4. 101.0°C

Profile image of Sayeda Mahfuja Rahman
8 Years agoGrade 12th pass
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2 Answers

Profile image of Chhavi Jain
8 Years ago
Dear student , 
 
Use the formula : 
                                      ΔTb = Kb m
 
                                   Tb –  Tbo  = 0.51 * 0.1 =0.051 
                                    
Since water boils at 373.15 K  , So  Tbo = 373.15 K
          
                       Therefore ,  T- 373.15 = 0.051
                                  
                                           Tb  = 373.201  K (  bp of aq. NaCl sol.)
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Profile image of Science
7 Years ago
Tb-100= i*kb*m
 
 
 
 
 
 
Tb=100+(2*0.51*0.1)
 
 
 
 
 
Tb=100.102°C 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
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