Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
the ip of h is 13.6 ev. it is exposed to electromagnetic waves of 1028A and given out induced radiations. find the wavelength of these induced radiations
Dear Kabir H-atom is exposed to UV radiation having wavelength 102.8nm the energy of photon corresponding to 102.8 nm waveegth is E = hc/λ = 1242 eV-nm /102.8 nm = 12.42 eV The energy needed to take athe H atom frm ground state to first excited state is E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV and to the second excited state is E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV and to the third excited state is E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV thus 12.42 eV photon has large probability of being absorbed in 12.1 eV The corresponding waveegth is: λ =103 nm RegardsArun
H-atom is exposed to UV radiation having wavelength 102.8nm
the energy of photon corresponding to 102.8 nm waveegth is
E = hc/λ = 1242 eV-nm /102.8 nm
= 12.42 eV
The energy needed to take athe H atom frm ground state to first excited state is
E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV
and to the second excited state is
E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV
and to the third excited state is
E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV
thus 12.42 eV photon has large probability of being absorbed in 12.1 eV
The corresponding waveegth is: λ =103 nm
Regards
Arun
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -