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The ionization energy of hydrogen atom is 13.6 eV. The second ionization energy of He+ would be 13.6 eV 27.2 eV 40.8 eV 54.4 eV Please explain.

The ionization energy of hydrogen atom is 13.6 eV.  The second ionization energy of He+ would be
  1. 13.6 eV
  2. 27.2 eV
  3. 40.8 eV
  4. 54.4 eV
Please explain.

Grade:11

1 Answers

Ankit Sharma
77 Points
8 years ago
answer is 27.2 eV 
IONIZATION ENERGY IS DIRECTLY PROPORTIONAL TO   Z2 /N2
 
Z = ATOMIC NO.
N= NO. OF SHELL OR ORBIT
 
 
 
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