MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass 
        
THE IONIZATION ENERGY FOR HYDROGEN ATOM IS 13.6 eV THEN REQUIRED ENERGY IN eV TO EXCITE IT FROM THE GROUND STATE TO 1ST EXCITED STATE?
3 months ago

Answers : (1)

Apurva Sharma
192 Points 
							
E=13.6 Z2/n2 eV/atom
thus for 1st exited state of H, n=2
and for H,Z=1
thus putting the values in the equation
E= 13.6(1)2/22 = 3.4 eV/atom energy
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Physical Chemistry

How do you use the Arrhenius concept to explain the basicity of Na2CO3 and NaNH2? Answer & Earn Cool Goodies
4A (g) -------> B(g) + 2C(g) initial pressure is given =800mm of hg after 10 minutes final pressure... Answer & Earn Cool Goodies
Is the most electronegative atom the periodic table, the smallest in its period?
Calculate the molarity of a solution containing 5g of NaOH in 450 mL solution
What is meant by degree of dissociation and degree of ionisation...?
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details