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THE IONIZATION ENERGY FOR HYDROGEN ATOM IS 13.6 eV THEN REQUIRED ENERGY IN eV TO EXCITE IT FROM THE GROUND STATE TO 1ST EXCITED STATE?

THE IONIZATION ENERGY FOR HYDROGEN ATOM IS 13.6 eV THEN REQUIRED ENERGY IN eV TO EXCITE IT FROM THE GROUND STATE TO 1ST EXCITED STATE?

Grade:12th pass

1 Answers

Apurva Sharma
220 Points
5 years ago
E=13.6 Z2/n2 eV/atom
thus for 1st exited state of H, n=2
and for H,Z=1
thus putting the values in the equation
E= 13.6(1)2/22 = 3.4 eV/atom energy

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