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THE IONIZATION ENERGY FOR HYDROGEN ATOM IS 13.6 eV THEN REQUIRED ENERGY IN eV TO EXCITE IT FROM THE GROUND STATE TO 1ST EXCITED STATE?
E=13.6 Z2/n2 eV/atomthus for 1st exited state of H, n=2and for H,Z=1thus putting the values in the equationE= 13.6(1)2/22 = 3.4 eV/atom energy
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