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the half life period of 1 st order reaction is 10 minutes .the time required for the concentraton of reactant to change from 0.08M to 0.06M

the half life period of 1st order reaction is 10 minutes .the time required for the concentraton of reactant to change from 0.08M to 0.06M

Grade:12

2 Answers

Arun
25750 Points
4 years ago
K = 0.693/t1/2
k = 0.693/10 = 0.0693
 
ln (0.08/0.02) = kt
 
ln 4 = kt
 
hence t = 20 minutes
 
Hope it helps
 
Vikas TU
14149 Points
4 years ago
Dear student 
The above ans is incorrect.
We know that half -life is related to K as
K = 0.693t1/2
given t1 /2 = 10 min
thus K = 0,693 x 10 min = 0.0693min-1
t = 2.303/K log [R0]/[R]
= 2.303/0.0693 log [0.08]/[0.06]
= 4.15 minute.
 
 
 

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