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THE EYES OF CERTAIN MEMBER OF A REPTILE FAMILY PASS A VISUAL SIGNAL TO THE BRAIN,WHEN THE VISUAL RECEPTORS ARE STRUCK BY PHOTONS OF WAVELENGHT 850NM.IF A TOTAL ENERGY OF 3.15*10^-14 IS REQUIRED TO TRIP THE SIGNAL, WHAT IS THE MINIMUM NUMBER OF PHOTONS THAT MUST STRIKE TE RECEPTORS?

HARSH , 7 Years ago
Grade 11
anser 1 Answers
anil kumar

Last Activity: 7 Years ago

We know that energy of one photon of lambda wavength is E=hc÷lambdaSo let n photons pass Then , E=n*hc÷lambdaE , lambda is given and h & C are const so so can calculate n.

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