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The enthalpies of combustion of carbon and carbon monoxide are -393.5and -283 kJ mol -1 respectively. The enthalpy of formation of carbonmonoxide per mole is?

babi , 9 Years ago

Grade 12

3 Answers

Sakshi

Last Activity: 8 Years ago

hey student..
for this question you need to keep in mind the definations of both the enthalipies written over there in the question. then try writing the reactions one by one. also try to use the hess law of thermodynamics for the above mentioned question and you ll be getting the answer..

arun

Last Activity: 8 Years ago

in this given enthalpy of combustion for C then reaction for combustion of carbon $C_{(s)} + O_{2}_{(g)} \rightarrow CO_{2}_{(g)}$ $\Delta H= - 393.5$ KJ/mol

and reaction for combustion of carbon-mono-oxide is $CO_{(g)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{2(g)}$ $\Delta H= -283$ KJ/mol

reversing this equation $CO_{2(g)} \rightarrow CO_{(g)} + \frac{1}{2}O_{2(g)}$ $\Delta H = 283$ KJ/mol

adding this equation with the equation of enthalpy of combustion of carbon

$C_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)}$ $\Delta H = -393.5 + 283$ = 110.5 KJ/mol

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,

Please find the answer to your question.

Write both the equation with their enthalpy of combustion.

Write the desired equation, and use the hess law to obtain your answer,

We get, ΔH = – 393.5 + 283 = 110.5 KJ/mol

Thanks and regards,

Kushagra

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