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the edge length of FCC is 508 pm if the radius if the cation is 110 pm the radius of anion is

 the edge length of FCC is 508 pm if the radius if the cation is 110 pm the radius of anion is

Grade:12

2 Answers

Vasantha Kumari
askIITians Faculty 38 Points
9 years ago

Here, we know that in FCC arrangement(ionic substance),

2(r+ + r) = edge length

2(110 + r) = 508

R=144 pm

Thanks & Regards,

Vasantha Sivaraj,

askIITians faculty

milind
23 Points
9 years ago
vasantha madam ….…...is rc mukherjee contains electrochemistry part to..............

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