Grade 11AIPMTThe dissociation constant of acetic acid at a given temperature is 1.69 ×10^-5.The degree of dissociation of 0.01 M acetic acid in presence of 0.01M HCl is a)0.42 b)0.13 c)0.169×10^-2 d)0.013 ayusha 8 Years agoGrade 11
Arun8 Years agoDear student [H30]+ = 0.01 + Ca = 0.01 M[CH3COO]- = Ca = 0.01 a[CH3COOH] = 0.01 1.69 * 10-5 = (0.01)(0.01 a)/(0.01)0.01 a = 1.69 * 10-5a = 1.69 * 10-3a = 0.169 * 10-2Hence option C is correct.RegardsArun (askIITians forum expert)