The dissociation constant of 0.01 M CH 3 COOH is 1.8 x 10 -5 , then calculate CH 3 COO - concentration in 0.1 M HCl solution. (Ans: 1.8 x 10 -6 M)

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sasankreddyvippala · Answer

CH3COOH=(CH3COO-)+(H+).due common ion effect H+ concentration is taken from HCl .Dissociation constant for CH3COOH is 1.8×10^-5..K=(concentration of CH3COO-)(concentration of H+)÷(concentration of CH3COOH)........by simplyfing we get concentration of CH3COOH is 1.8×10^-6

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The dissociation constant of 0.01 M CH 3 COOH is 1.8 x 10 -5 , then calculate CH 3 COO - concentration in 0.1 M HCl solution. (Ans: 1.8 x 10 -6 M)

The dissociation constant of 0.01 M CH₃COOH is 1.8 x 10^-5, then calculate CH₃COO^- concentration in 0.1 M HCl solution.
(Ans: 1.8 x 10^-6 M)

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The dissociation constant of 0.01 M CH 3 COOH is 1.8 x 10 -5 , then calculate CH 3 COO - concentration in 0.1 M HCl solution. (Ans: 1.8 x 10 -6 M)

The dissociation constant of 0.01 M CH3COOH is 1.8 x 10-5 , then calculate CH3COO- concentration in 0.1 M HCl solution.(Ans: 1.8 x 10-6 M)

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The dissociation constant of 0.01 M CH₃COOH is 1.8 x 10^-5, then calculate CH₃COO^- concentration in 0.1 M HCl solution.
(Ans: 1.8 x 10^-6 M)