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`        The density of a 3 M sodium thiosulphate solution (Na2S2O3) is 1.25 g per ml. Calculated (i) the percentage by weight of sodium thiosulphate, (ii) the mole fraction of sodium thiosulphate and (iii) the molalities of Na+ and S2O32- ions.`
5 years ago

Jitender Pal
365 Points
```
(i) Mole fraction = Moles of substance/Total moles

(ii) 1 mole of Na2S2O3 gives 2 moles of Na+ and 1 mole S2O32-

Molecular wt. of sodium thiosulphate solution (Na2S2O3) = 23 * 2 + 32 * 2 + 16 * 3 = 158

(i) The percentage by weight of Na2S2O3

= wt of Na2S2O3/wt of solution * 100 = 3 * 158 * 100/100 * 1.25 = 37.92

[wt. of Na2S2O3 = Molarity * Molwt]

(ii) Mass of 1 litre solution = 1.25 * 1000 g = 1250 g

[∵ density = 1.25g/l]

Mole fraction of Na2S2O3

= Number of moles of Na2S2O3/Total number of moles

Moles of water = 1250 – 158 *3/18 = 43.1

Mole fraction of Na2S2O3 = 3/3 + 43.1 = 0.065

(iii) 1 mole of sodium thiosulphate (Na2S2O3) yields 2 moles

of Na+ and 1 mole of S2O2-3

Molality of Na2S2O3 = 3 * 1000/776 = 3.87

Molality of Na+ = 3.87 * 2 = 7.74m

Molality of S2O2-3 = 3.87m

```
5 years ago
R Parker
40 Points
```							Calculate the mass of given solution using Density = mass /volumeMass of 1000 ml of 3M solution will be given by density x volume = 1.25 g ml-1 x 1000 ml = 1250 g​Mass of Na2S2O3 in 1000 ml solution = molar mass of Na2S2O3 x number of moles of solute                                               = 158 g/mol x 3 mol​                                             = 474 g​Mass of the solvent = mass of solution - mass of Na2S2O3                            = 1250 g - 474 g =776 g​Moles of Na2S2O3 = 3 mol ( 3 M) givenMoles of solvent water = mass of water/molar mass of water = 776 g/18 gmol-1​ = 43.1 molTotal number of moles in solution = 3 + 43.1 = 46.1 mol​Mole fraction of Na2S2O3 = moles of Na2S2O3 /total moles = 3/46.1 = 0.065 Molality of solution = moles of solute/solvent in kg                            = 3 mol / 0.776 kg = 3.865 mol·kg-11 mole of Na2S2O3 gives 2 moles of Na+ So, molality of Na+  is 2 x 3.865 = 7.73 mol.kg-1​​1mole of Na2S2O3 gives 1 moles of S2O32- So, molality of S2O32- is 3.865mol.kg-1
```
one year ago
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