The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

(A) 1.73 ´ 10-4 M min-l
(B) 2.47 ´ 10-4 M min-l
(C) 3.47 ´ 10-5 M min-l
(D) 1.73 ´ 10-5 M min-l

Question

Nirgun · Answer

k=2.303/t log(a/a-x) a=0.1M a-x=0.025M t=40min k=2.303/40 log (0.1/0.025) =0.0347^-1 min^-1 Rate as it is 1 st order Rate dx/dt=R[a]^1 = 0.0347*0.01 =3.4*10^-4 Mmin^-1

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The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be (A) 1.73 ´ 10-4 M min-l (B) 2.47 ´ 10-4 M min-l (C) 3.47 ´ 10-5 M min-l (D) 1.73 ´ 10-5 M min-l

The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

(A) 1.73 ´ 10-4 M min-l
(B) 2.47 ´ 10-4 M min-l
(C) 3.47 ´ 10-5 M min-l
(D) 1.73 ´ 10-5 M min-l

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The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be (A) 1.73 ´ 10-4 M min-l (B) 2.47 ´ 10-4 M min-l (C) 3.47 ´ 10-5 M min-l (D) 1.73 ´ 10-5 M min-l

The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be (A) 1.73 ´ 10-4 M min-l (B) 2.47 ´ 10-4 M min-l (C) 3.47 ´ 10-5 M min-l (D) 1.73 ´ 10-5 M min-l

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The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

(A) 1.73 ´ 10-4 M min-l
(B) 2.47 ´ 10-4 M min-l
(C) 3.47 ´ 10-5 M min-l
(D) 1.73 ´ 10-5 M min-l