Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be (A) 1.73 ´ 10-4 M min-l (B) 2.47 ´ 10-4 M min-l (C) 3.47 ´ 10-5 M min-l (D) 1.73 ´ 10-5 M min-l

The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

(A) 1.73 ´ 10-4 M min-l
(B) 2.47 ´ 10-4 M min-l
(C) 3.47 ´ 10-5 M min-l
(D) 1.73 ´ 10-5 M min-l

Grade:12

1 Answers

Nirgun
13 Points
one year ago
k=2.303/t log(a/a-x)
a=0.1M
a-x=0.025M
t=40min
 
 
k=2.303/40 log (0.1/0.025)
 =0.0347^-1 min^-1
 
Rate as it is 1st order
Rate  dx/dt=R[a]^1
                 = 0.0347*0.01
                 =3.4*10^-4 Mmin^-1

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More

10th iCAT Scholarship Test Registration Form