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Grade: 11

                        

The bond enthalpies of gas H2 , Cl2 and HCL are 104, 58 ,103 bar3 k-1 mol-1 .calculate the enthalpy of formation of HCl

3 years ago

Answers : (1)

Arun
24737 Points
							
1. The chemical equation for the formation of HCl is :

      H2 + Cl2 =2 HCl
2. Bond dissociation energy = Bonds broken - Bonds formed
                                            = (104 + 58) - 2 (103) = - 44 Kcal.
3 years ago
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