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the boiling point of an aqueous solution of a non volatile solute is 100.15 0 C .what is the freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water? the values of K b and K f for water are 0.512 0 C and 1.86 0 C K molal -1 the boiling point of an aqueous solution of a non volatile solute is 100.150C .what is the freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water? the values of Kb and Kf for water are 0.5120C and 1.860C K molal -1
For boiling point,Tb = i * kb * M100.15 + 273 = 1*0.512*Mfrom here calculate M.After adding 500 ml water,molarity becomes,M x V = M’ x 2VM’ = M/2Then apply,Tf = 1*kf*M’
this the attcahment of the question that u want to knowankit singhmanit bhopalthope the answer is useful to u keep it up work hard to fullfill your drea
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