×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
the boiling point of an aqueous solution of a non volatile solute is 100.15 0 C .what is the freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water? the values of K b and K f for water are 0.512 0 C and 1.86 0 C K molal -1
the boiling point of an aqueous solution of a non volatile solute is  100.150C .what is the freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water? the values of Kb and Kf for water are 0.5120C and 1.860C K molal -1

```
4 years ago

Vikas TU
14149 Points
```							For boiling point,Tb = i * kb * M100.15 + 273 = 1*0.512*Mfrom here calculate M.After adding 500 ml water,molarity becomes,M x V = M’ x 2VM’ = M/2Then apply,Tf = 1*kf*M’
```
4 years ago
ankit singh
609 Points
```							this the attcahment of the question that u want to knowankit singhmanit bhopalthope the answer is useful to u keep it up work hard to fullfill your drea
```
5 months ago
ankit singh
609 Points
```							  For boiling point,Tb = i * kb * M100.15 + 273 = 1*0.512*Mfrom here calculate M.After adding 500 ml water,molarity becomes,M x V = M’ x 2VM’ = M/2Then apply,Tf = 1*kf*M’
```
5 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions