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the boiling point of an aqueous solution of a non volatile solute is 100.15 0 C .what is the freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water? the values of K b and K f for water are 0.512 0 C and 1.86 0 C K molal -1
For boiling point,Tb = i * kb * M100.15 + 273 = 1*0.512*Mfrom here calculate M.After adding 500 ml water,molarity becomes,M x V = M’ x 2VM’ = M/2Then apply,Tf = 1*kf*M’
this the attcahment of the question that u want to knowankit singhmanit bhopalthope the answer is useful to u keep it up work hard to fullfill your drea
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