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The balanced chemical equation for the formation of ammonia gas by the reaction between nitrogen gas an hydrogen gas is given. N2 ​ + 3 H2 → 2 N H3 ​ How many moles of ammonia are formed when 6 moles of N2 ​ react with 6 moles of H2 2 ​ ?

The balanced chemical equation for the formation of ammonia gas by the reaction between nitrogen gas an hydrogen gas is given.
N2
​+3H2→2NH3
​
How many moles of ammonia are formed when 6 moles of N2
​ react with 6 moles of H22​?

Grade:11

1 Answers

Adarsh Pal
askIITians Faculty 159 Points
3 years ago
Given reaction for the formation of ammonia-
N2​+3H2​⟶2NH3​
From the above reacton,
1 mole of N2​ reacts with 3 moles of H2​.
Therefore,
6 moles of N2​ will react with 18 moles of H2​.
Given amount of H2​=6 moles
Therefore, H2​ is the limiting reagent.
Therefore,
Again from the above reaction.
No. of moles of ammonia formed when 3 moles of H2​ react with excess of N2​=2
∴ No. of moles of ammonia formed when 6 moles of H2​ react with excess of N2​=32​×6=4 moles
Hence 4 moles of ammonia are formed when 6 moles of N2​ react with 6 moles of H2​.

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