The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is? (a) 0.433 (b)0.3535 (c)2.83 (d)2.309

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Karam singh · Answer

Ag crysallises in FCC unit cellSo in FCC unit cell sqrt(2)×a=4r where a=edge length r=radiusSo answer will be 4/1.41=2.83

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The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is? (a) 0.433 (b)0.3535 (c)2.83 (d)2.309

The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is?

(a) 0.433 (b)0.3535 (c)2.83 (d)2.309

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The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is? (a) 0.433 (b)0.3535 (c)2.83 (d)2.309

The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is? (a) 0.433 (b)0.3535 (c)2.83 (d)2.309

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The approximate ratio of the length of edge of unit cell (l) and atomic radius (r) in crystal lattice of metal Ag is?

(a) 0.433 (b)0.3535 (c)2.83 (d)2.309