The angular momentum of an electron in Bohr’s orbit of He+ is 3.1652*10^-34 kgm^2/sec. what is wave number in terms of rydbergs constant (R) of the spectral line emitted if an electron falls from this level to first excited state ( using h=6.626*10^-34 Joule second. )

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Eshan · Answer

Dear student, Angular momentum in Bohr&rsquo;s orbit is quantized and is equal to The electrons falls from this level to first excited state, that is, n=2. Hence the wave number of emitted line=

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The angular momentum of an electron in Bohr’s orbit of He+ is 3.165210^-34 kgm^2/sec. what is wave number in terms of rydbergs constant (R) of the spectral line emitted if an electron falls from this level to first excited state ( using h=6.62610^-34 Joule second. )

The angular momentum of an electron in Bohr’s orbit of He+ is 3.165210^-34 kgm^2/sec. what is wave number in terms of rydbergs constant (R) of the spectral line emitted if an electron falls from this level to first excited state ( using h=6.62610^-34 Joule second. )

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