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the amount of glucose to be dissolved in 500g of water so as to produce the same lowering in vapour pressure as that of 0.2 molal aqeous urea solution is ?

the amount of glucose to be dissolved in 500g of water so as to produce the same lowering in vapour pressure as  that of 0.2 molal aqeous urea solution is ?

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Grade:11

1 Answers

Madhavi
31 Points
6 years ago
For urea :m=0.2 and m=moles of urea(n)*1000/mass of solventSo, n*1000/mass of solvent=0.2By this, relative lowering in vapour pressure =n*molar mass of solvent/mass of solvent=0.2*18/1000=3.6/1000 .....(1)For glucose : relative lowering in vapour pressure =n*molar mass of solvent(water)/mass of water=mass of glucose (W)*18/180*500 =W/5000 ........(2)From 1and2,3.6/1000=W/5000So W=18g

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