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Grade: 11
        
the amount of glucose to be dissolved in 500g of water so as to produce the same lowering in vapour pressure as  that of 0.2 molal aqeous urea solution is ?
10 months ago

Answers : (1)

Madhavi
31 Points
							For urea :m=0.2 and m=moles of urea(n)*1000/mass of solventSo, n*1000/mass of solvent=0.2By this, relative lowering in vapour pressure =n*molar mass of solvent/mass of solvent=0.2*18/1000=3.6/1000      .....(1)For glucose : relative lowering in vapour pressure =n*molar mass of solvent(water)/mass of water=mass of glucose (W)*18/180*500 =W/5000                   ........(2)From 1and2,3.6/1000=W/5000So W=18g
						
10 months ago
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