SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s) For the reacti

Question

SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s)For the reaction, Calculate Kp at 900K where the equilibrium steam hydrogen mixture was 35% H2 by volume.a)3.448 b)2.987 c)5.762 d)3.100

Arun · Accepted Answer

In the reacn. SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l)Since solid and liquid states compounds would not take part in Kc or Kp.Hence, from chemical eqn., SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l) t=0 V 0 t=t V – 2x 2xNow given => 2x = 0.35(V – 2x)solving we get x = 0.35V/0.8 => 7V/16Hence Fnal volume becomes, at t=t Kc = [(H2O)/(H2)]^2 = > [(2x)/(V-2x)]^2 = > 0.35^2 = > 12.25/100 = > 0.1225. Kp = Kc*(RT)^nn = 3 – 2 = 1Kp = 0.1225*0.0821 * 900 = > 9 (approx.)

Inorganic Chemistry> SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s) For th...

SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s)
For the reaction, Calculate Kp at 900K where the equilibrium steam hydrogen mixture was 35% H2 by volume.
a)3.448 b)2.987 c)5.762 d)3.100

Arya More , 7 Years ago

Arun

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Inorganic Chemistry> SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s) For th...

SnO2(s) + 2H2(g) = 2H2O(g) + Sn(s)For the reaction, Calculate Kp at 900K where the equilibrium steam hydrogen mixture was 35% H2 by volume.a)3.448 b)2.987 c)5.762 d)3.100

Arya More , 7 Years ago

Arun

LIVE ONLINE CLASSES

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