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Grade: 11
        
Sir kindly give the answer for question number"1" in exercise 6.
Please send me the solution in a detailed manner
 
21 days ago

Answers : (1)

Arun
15885 Points
							
Dear student
 
Initial pH = 1, i.e. [H+] = 0.1 mole/litre
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1= M2V2
0.1 ×1 =0.01 × V2
V2= 10 litre.
Volume of water added = 9 litre.
 
Regards
Arun (askIITians Forum expert)
20 days ago
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