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Sir, In zero order reaction we write the slope to be m=-k But according to the eqn we get i.e., t=1/k([Ro]-[R]) Therefore the slope must be m=1/k Why dont we write it so.


6 years ago

Pankaj
131 Points
							Integrated rate law
for a zero order reaction is :

[R]=-kt +[R]0

When we compare the equation with the equation of a straight
line i.e. y = mx + c,

we get slope of line =
m = -k and Y intercept = [R]0

Slope is equal to –k for the plot [R] vs t

Same equation can also be written as

t = 1/k([Ro]-[R])

When
compared with the equation of straight line y = mx + c

The slope would be 1/k
for the plot t vs ([Ro]-[R]) and the y intercept would be 0 as c = 0

Hope
it’s clear to you.

Thanks &
Regards

Pankaj Singh


6 years ago
Pankaj
131 Points
							Integrated rate lawfor a zero order reaction is :

[R]=-kt+[R]0

When we compare the equation with the equation of a straightline i.e. y = mx + c,

we get slope of line =m = -k and Y intercept =[R]0

Slope is equal to –k for the plot [R] vs t

Same equation can also be written as

t = 1/k([Ro]-[R])

Whencompared with the equation of straight liney = mx + cThe slope would be 1/k
for the plott vs ([Ro]-[R]) and the y intercept would be 0 as c = 0Thanks and RegardsPankaj SinghaskIITians Faculty

6 years ago
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• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions