Sir, help me to solve with easiest description you can.
Amit , 8 Years ago
Grade 11
Physical Chemistry> Sir, help me to solve with easiest descri...
1 Answers
Himanshu
Last Activity: 8 Years ago
No of moles of CO2 initially = weight of substance(gm)/ molecular mass
No.of moles of CO2 initially = 0.2/44 = 1/220 mol
No. of moles removed = no. of molecules/ avagardo constant
No. of moles removed = 1021/ (6 × 1023) = 1/600 mol
No. of moles left = 1/220 – 1/600 = 0.028 (approx.)
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