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sir can i know how to solve this questionif electronegetivity of A is 2 and B is 3 what is the covalent character percentage of the bond A-B

V.P. Aruna Devi , 8 Years ago
Grade 12
anser 1 Answers
Bhavya

Last Activity: 8 Years ago

Dear student
% ionic character = 16 (Xb – Xa) + 3.5 (Xb – Xa)2
= 16 (3-2) + 3.5 (3-2)2
= 16 + 3.5 = 19.5%
% covalent character = 100-19.5 = 80.5%

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