silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.9pm. calculate the density of silver .9atomic wt=107.9u)

Question

Khimraj · Answer

Silver forms ccp therefore the number of Silver atoms per unit cell ,z = 4 Molar mass of Silver ,M=107.9 g/mol = 107.9x10 -3 kg/mol Edge length of unit cell ,a=408.6 pm = 408.6x10 -12 m Density d = z*M/a 3 *N A = 10.5 g/cm 3 Hope it clears.......................

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silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.9pm. calculate the density of silver .9atomic wt=107.9u)

silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.9pm. calculate the density of silver .9atomic wt=107.9u)

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silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.9pm. calculate the density of silver .9atomic wt=107.9u)

silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.9pm. calculate the density of silver .9atomic wt=107.9u)

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