d=mv 10.5 g/cc
Number of atoms of Ag in 1cc ⇒ 10.5108×NA
In 1cm, number of atoms of Ag = 310.5108×NA−−−−−−−−√
In 1cm2
, number of atoms of Ag = =(10.5108×NA)2/3
In 10–12m2 or 10–8cm2
, number of atoms of
Ag=(10.5108×NA)23 × 10−8 =((10.5×6.02×1023)108)23 × 10−8
=1.5×107
Thus, x = 7