Flag Physical Chemistry> see attachment and explain
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see attachment and explain

Shivam , 10 Years ago
Grade 12
anser 1 Answers
Apoorva Arora

Last Activity: 10 Years ago

De broglie wavelength is given by

where lambda is wavelength and P is momentum and h is planck's constant.
So,
Also,
where M is mass and E is energy , Since energy is the same.
which is=2
Thanks and Regards
Apoorva Arora
IIT Roorkee
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