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Rate constant of first order reaction is 0.016/minute calculate time required for80% of reaction to be completed

Gnana Sai Nuthakki , 7 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

 
For the principal arrange response: 
k = (2.303/t) log (a/a – x) t= ?, when x = 0.8 a 
From above, k = 0.016 min-1 
Along these lines, t = (2.303/0.016) log (a/a – 0.8 a) 
= (2.303/0.016) log (1/0.2) = 1.58437 min 
The time at which the response will be 80% finished is 1.58437 min. 

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