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question is attached in image whose ANSWER IS 5.IT IS A SINGLE INTEGER VALUE TYPE QUESTION

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2 years ago

Arun
24738 Points
```							Suppose runner and cyclist reach at same position in time t, and the observer has travelled x distance in this time Speed of runner= 15 km/h=25/6 m/sspeed of cyclist=25 km/h = 125/18 m/s Time t = distance travelled/speed        t   = (20-x)/(25/6) = (30-x)/(125/18)x=5mputting in eqn to get t= 18/5Speed of observer to travel 5 meter distance in 18/5 sec= >5/v=18/5 =>v=25/18 m/s =5 km/h
```
2 years ago
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• Test paper with Video Solution
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• NCERT Solutions
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