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Grade 12th passOrganic Chemistry

Question from ionic equilibria the answer is third option please explain the concept and the equation used. I did it with common ion effect still I didn`t get the answer

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Profile image of Sanskrit gupta
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
8 Years ago
Dear student
 
 

The dissociation of the above salt can be written as: Pb(OH)2====Pb(+2) + 2(OH-)

Therefore, the equation of Ksp=[Pb+2][OH-]^2

In present case, you are given that Ksp=1.2x10^-5 and [Pb+2]=0.12M.

You can calculate [OH-]=square root(1.2x10^-5/.012)=10^-4

Therefore, pOH=-log(10^-4)=log(10^4)=4

pH=14-pOH i.e pH=14–4=10

Thus, the pH of the solution must be 10.

 

 

Hence option B is correct.

 

 

Regards

Arun (askIITians forum expert)

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