×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Q1: The momentum of a body increases by 20%. What is the % increase in it`s K.E .Q2: two vectors of magnitude 3 & 4 have resultant 5, the angle between vectors is ?Please solve these questions for me. I have Medical University Test on 21st Oct.

```
3 years ago

Arun
25211 Points
```							Kinetic Energy=(1/2)m(v^2) ;Momentum(p)=mv ;Kinetic Energy={ (mv)^2}/2m={(p)^2}/2mwhere m=Mass of a body and v=VelocityMomentum=pIncrease in Momentum=20%So New Momentum (p')=p * {1+ (20/100)} =1.2 pNew Kinetic energy={(p')^2}/2m(p')^2= (1.2 p)^2=1.44 pAs mass of a body is constantTherefore % Increase in K.E.= 44%(1.44p-p=0.44p) Now cor 2nd question,As 3,4 and 5 makes a Pythagorean triplet,That means angle between 3 and 4 unit vectors is 90 degree
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions