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Grade: 12th pass
        
pressure would be..? 
if we decrease the volume by 45%at constant temperature 
one year ago

Answers : (1)

Sahani Kumar
99 Points
							
Initial volume = V1
 initial pressure = P2
V2=(V1 –( 45*V1/100))=(55 *V1)/100
P2 =?
 We know that at constant temperature 
P1 * V1=P2 * V2  
on putting the value of V2 we get
P1*V1=P2*(55V1/100)
On solving this equation we get 
P2=( 100 P1/55)
P2=1.81P1
 Regards 
Askiitian member 
If you liked the answer please encourage us by approving the answer. 
one year ago
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