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Grade: 11

                        

Potassium acid oxalate K2C2O4.3H2C2O4.4H20 can be oxidized by MNO4- in acidic medium.Calculate the volume of 0.1M KMnO4 reacting in acid solution with one gram of acid oxalate.

3 years ago

Answers : (1)

Khushi
13 Points
							here n factor of MnO-4= 7 also, n factor of Mn2+= 2so required n factor = 5n factor of  k2c2o4.3HC2o4.4H20=8nowmilliequivalent of KMnO4=milliequivalent of  potassium acid oxalate(k2c2o4.3HC2o4.4H20)n factor* molarity *volume=w/E * 1000E= molecular weight/ n factorE=molecular weight of k2c2o4.3HC2o4.4H20 / 8E=505/8W=1 gram (given in the question)5*0.1*v= 1/505/8 *1000v=80000/2525v=31.6
						
one year ago
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