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Plzzzzzz answer urgently..............................................................................

Plzzzzzz answer urgently..............................................................................

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Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
Dear student
 
 

we can add or subtract electrode potential but  can be done with dG 

dG =-nFE

f is const so -nF can be used 

ocl-/cl-  n=2

cl-/2cl2 n=4

ocl-/2cl2 n=4

2*0.94 - 4*(-1.36)=4*E

now E is electrode potential required

 E=1.83V

 

 

Regards

Arun (askIITians forum expert)

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