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`        Plz answer this..An open flask contains air at 27°C. Calculate the fraction of air that would be expelled at 476°C`
10 months ago

```							Initial Pressure (P1) = 1 atmInitail Temperature (T1) = 27*C = 300 KFinal Pressure (P2) = P1 = 1 atm​Final Temperature (T2) = 127*C = 400 KInitial Volume (V1) = VFinal Volume (V2) = V'Using Combined Gas Equation, we get:P1V1T1 = P2V2/T2​Substituting the values, we get: V' = 4V/3 But, the flask can hold only V volume of air.This makes us realise that some air has been expelled out of the flask.=> Volume of air expelled = 4V/3 - V = V/3From this, we can get the fraction of air expelled out = Amount of air expelled/Final volume=>  Fraction of air expelled out = V/3 / 4V/3 = 1/4
```
10 months ago
```							Dear student Here is the assumptions and detailed explanation Assumptions :Volume of flask is constantAir at 27 °C & 1 atm is behave like Ideal Gas.Expansion of flask due to heat in nilSo, if gas to be expel 1/4th of Volume (it is final Volume, not initial) then it has to expand in sich way that it's final volume would be Volume of flask + 1/4 th of Gas (final volume).Assume, Volume of flask = VInitial Conditions,T = 27 °C = 300 KVolume = VFinal Conditions,Final Temp = T”Final Volume (V') = V + 1/4 of V'V' = V + V'/4V' - V'/4 = V3V’/4 = VV' = 4V/3From ideal gas equation, we know that volume and temperature are directly proportional.V/T = V'/T”T” = T × V'/VT” = T × 4/3V/VT” = T × (4/3)T” = (4/3)×300T” = 400K = 127 °CSo, at 127 °C, gas will expel it's 1/4th volume out of flask.Final volume will not be equal to 5/4 time of initial volume, because in question it mentioned that, it expel 1/4 of it's gas volume, not flask volume. So it will expel 1/4 of it's final volume.
```
10 months ago
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