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Pls explain formulae for ionic product of water 2.303 log (Kw2/Kw1)=Delta H/R*(T2-T1)/T1T2

Devashmita Sinha , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Water atoms can work as both acids and bases. One water particle (going about as a base) can acknowledge a hydrogen particle from a moment one (going about as a corrosive). This will happen anyplace there is even a hint of water - it doesn't need to be unadulterated. A hydroxonium particle and a hydroxide particle are framed. 
Be that as it may, the hydroxonium particle is an extremely solid corrosive, and the hydroxide particle is an exceptionally solid base. As quick as they are framed, they respond to poduce water once more. The net impact is that a balance is set up. 
At any one time, there are unfathomably little quantities of hydroxonium particles and hydroxide particles display. Additionally down this page, we should ascertain the convergence of hydroxonium particles display in immaculate water. It ends up being 1.00 x 10-7 mol dm-3 at room temperature. You may well discover this harmony written in a streamlined for = e connection amongst Kw and pKw is precisely the same as that amongst Ka and pKa, or [H+] and pH. 
The Kw estimation of 1.00 x 10-14 mol2 dm-6 at room temperature gives you a pKw estimation of 14.

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