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Please tell how to approach question no. 17 and 19 Elements A and B form two compounds B 2 A 3 and B 2 A. O.05 moles of B 2 A 3 weight 9.0 g and 0.10 mol of B 2 A weight 10g SO FIND ATOMIC WEIGHT OF A & B... Please tell how to approach question no. 17 and 19Elements A and B form two compounds B2A3 and B2A.O.05 moles of B2A3 weight 9.0 g and 0.10 mol of B2A weight 10gSO FIND ATOMIC WEIGHT OF A & B...
Dear Ashif To find the atomic weight for the elements A and B, we will use the following formulas:Moles = mass/ molar mass.....molar mass= mass/molesHence you can calculate the molar mass of the compounds B2A3 and B2A using the above formulas.B2A3 ..... molar mass = 9g/ 0.05 = 900/5 = 180 Therefore relative formula mass of B2A3= 180that means, (atomic mass A)x 2 + (atomic mass B)x3 = 180 2A + 3B = 180Relative atomic mass of B2A:molar mass= mass / moles = 10g/0.1 moles = 100 u Therefore RAM of B2A= 100That means, (atomic mass B)x2 + atomic mass A= 100 2B + A = 100.....Solve the two equations by substitution;B2 + A3 =1802B + A = 100 ( A= 100 -2B)B2 + 3( 100 -2B) = 1802B + 300 - 6B = 1802B- 6B = 180-300 -4B = -120 (divide both sides by -4) B = 30substitute B to find A2B + A = 100(2 x30) + A = 100 60 + A = 100 A = 100 - 60 A = 40Therefore Atomic weight of A is 40 B is 30 RegardsArun (askIITians forum expert)
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