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Please tell how to approach question no. 17 and 19 Elements A and B form two compounds B 2 A 3 and B 2 A. O.05 moles of B 2 A 3 weight 9.0 g and 0.10 mol of B 2 A weight 10g SO FIND ATOMIC WEIGHT OF A & B...

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2 years ago

```							Dear Ashif To find the atomic weight for the elements A and B, we will use the following formulas:Moles = mass/ molar mass.....molar mass= mass/molesHence you can calculate the molar mass of the compounds B2A3 and B2A using the above formulas.B2A3 .....  molar mass =  9g/ 0.05                                     =  900/5   = 180     Therefore relative formula mass of B2A3= 180that means, (atomic mass A)x 2 + (atomic mass B)x3  =  180                    2A + 3B = 180Relative atomic mass of B2A:molar mass= mass / moles  =    10g/0.1 moles                                             =    100 u                                 Therefore RAM of B2A= 100That means,    (atomic mass B)x2 + atomic mass A= 100                         2B  +  A = 100.....Solve the two equations by substitution;B2 + A3 =1802B + A   = 100  ( A= 100 -2B)B2 + 3( 100 -2B) = 1802B + 300 - 6B = 1802B- 6B = 180-300 -4B = -120  (divide both sides by -4)    B  =  30substitute B to find A2B + A = 100(2 x30) + A = 100            60 + A = 100                                             A = 100 - 60                                              A = 40Therefore Atomic weight of A is 40                                                B is 30                      RegardsArun (askIITians forum expert)
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2 years ago
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