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5 years ago

ng29
1698 Points
```							this formula shows that  if there are 100 oxygen atoms , atoms of nickel are 98charge on 100 O2- ions = 100*(-2) =  – 200suppose Ni atoms as Ni+2 =  xthen Ni atoms on Ni+3 =  98-xtotal charge on Ni+2  and Ni+3  ===  2x + 3(98-x)  = 294 – xas metal oxide is neutral  total charge of cations is equal to that of anions294 – x =200x=94% of Ni as Ni+2 =  (94/98) * 100= 96 % % of Ni as Ni+3  =  4 %. APPROVE IF USEFUL
```
5 years ago
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