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Grade: 11

                        

Please help me with this question

5 years ago

Answers : (1)

ng29
1698 Points
							
this formula shows that  if there are 100 oxygen atoms , atoms of nickel are 98
charge on 100 O2- ions = 100*(-2) =  – 200
suppose Ni atoms as Ni+2 =  x
then Ni atoms on Ni+3 =  98-x
total charge on Ni+2  and Ni+3  ===  2x + 3(98-x)  = 294 – x
as metal oxide is neutral  total charge of cations is equal to that of anions
294 – x =200
x=94
% of Ni as Ni+2 =  (94/98) * 100= 96 % 
% of Ni as Ni+3  =  4 %.
 
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5 years ago
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