Nishant jorwal
Last Activity: 6 Years ago
Formula of magnetic moment is = n(n+2)
So, √n(n+2) = √35 B.M.
n(n+2)=35 . Therefore, n=5
Hence, the no. of unpaired electrons in the element will be 5
Now try the unpaired electrons in all the elements
then you will get option C ,i.e.26
It has configuration 4s2 3d6 first you will take out the 2 electrons present in s orbital and then 1 from d orbital because it has charge +3
After this it will have only 5 unpaired electrons.