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Grade: 11
        
Please give its detailed solution .
A mineral contained mgo=31.88% SiO2=63.37%and H20=4.75%. Find its empirical mass
 
5 months ago

Answers : (3)

Pooja
124 Points
							
Molecular masses are
MgO = 40
SiO2 = 60
H20 = 18
Finding moles
MgO = 31.88/40 = 0.797
SiO2 = 63.37/60 = 1.056
H20 = 4.75/18 = 0.264
Finding relative moles
MgO  = 0.797/ 0.264 = 3
SiO= 1.056/ 0.264 = 4
H20 =  0.264/ 0.264 = 1
So , the empherical formula is
Mg3O3Si4O8H2O
= H2Mg3Si4O12
5 months ago
Khimraj
3008 Points
							 
MgO = 31.88/40 = 0.797
SiO2 = 63.37/60 = 1.056
H20 = 4.75/18 = 0.264
relative moles -
MgO  = 0.797/ 0.264 = 3
SiO= 1.056/ 0.264 = 4
H20 =  0.264/ 0.264 = 1
 empherical formula = H2Mg3Si4O12
5 months ago
Pooja
124 Points
							
Khimraj , I don't understand why are you answering the questions I have already answered This actually happened 4th time
Just to earn points ?
Don't repeat  it and don't violate forum policy by copy pasting my answers
Disapprove 2nd answer that he has copy pasted
 
5 months ago
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