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Grade: 12th pass 

                        
Please explain the answer of the above question.the ques belongs to ionic equilibrium.
4 years ago

Answers : (1)

Bhavya
askIITians Faculty
1286 Points 
							Dear student
For complete neutralisation we apply,
N1V1 (HA) = N2V2(NaOH)
50*N = 100 *0.25
N = 0.5
Now,
HA   +  NaOH   --->   NaA  +   H2O
100*0.5   100*0.25     0
(excess)    (limiting)
number of corresponding milliequivalent are :-
50        25          25       25
it is a question of buffer so,
pH = pKa + log[salt]/[acid]
5 = pKa + log[25]/[25] = pKa + log1 = pKa   {log1=0}
5=pKa
4 years ago
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