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Please explain the answer of the above question.the ques belongs to ionic equilibrium.
Dear studentFor complete neutralisation we apply,N1V1 (HA) = N2V2(NaOH)50*N = 100 *0.25N = 0.5Now,HA + NaOH ---> NaA + H2O100*0.5 100*0.25 0(excess) (limiting)number of corresponding milliequivalent are :-50 25 25 25it is a question of buffer so,pH = pKa + log[salt]/[acid]5 = pKa + log[25]/[25] = pKa + log1 = pKa {log1=0}5=pKa
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