Percentage of Se in peroxidase enzymeis 0.5% by weight (Se= 78.4). Then the minimum molecular weight of peroxidase enzyme is (1) 3.13×10 ^4(2) 15.68(3) 1.568 ×10^3(4) 1.568×10^4
Vikash Kumar Singh , 7 Years ago
Grade 12th pass
1 Answers
Tanisha gandhi
Last Activity: 6 Years ago
If the weight of se =78.4In percentage =0.5% Then, 0.5%of 78.4= 78.4/0.5*100=15680 molNow we have been asked about the min mol value i.e. 1.5680*10^4
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