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`        One mole of N2O4 in a 1 L flask decomposes to attain the equilibrium N2O4(g)  2NO2(g) At the equilibrium the mole fraction of NO2 is 1/2. Hence Kc will be`
2 years ago

Vikas TU
9476 Points
```							                          N2O4          ============>                 2NO2t=0                     1 mol                                                       0t=teq.                1-x                                                           2xmole fraction of NO2 = 2x/(1-x+2x) => 2x/(x+1) = ½solving we get, 4x = x+13x = 1x = 1/3Kc = > (2x)^2/(1-x) => (2/3)^2/(1-1/3) => (4/9)/(2/3) => 4*3/9*2 => 2/3
```
2 years ago
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