One litre CO2 is passed through red hot coke. The volume becomes 1.4 litres at same temperature and pressure. the composition of products is: Ans: 0.6 L CO2 and 0.8 L CO

							Co2(g)+co(s)------2co(s)Initial vol.  (1L).      0.               0Final vol.   1-x.                         2xFinal vol.   1-x+2x=1.4                   X=0.4Vol of co2=2×0.4=0.8Vol of co=(1-0.4)=0.6
						

							Shit happens when this is asked in exams.
						

							
Co2+C= CO this is the unbalanced reaction when carbon dioxide is passed through red hot coke .for solving questions like this one should balance the above mentioned equation and proceed with solving the problems
						

							The reaction involved -co2 + c= 2co1L             2L Given total volume of composition 1.4L Actual volume of composition is 2L therefore, co2 left= actual volume -given volume                                      =2-1.4                                       =0.6 literNow,        co remains=given volume of composition -volume of co2                              =1.4-0.8                             = 0.6 liter
						

							
co2 + c----2co
let x lt of co2 cokvine with coke it will form 2xlt of co.
voluke of co2 left =1-x
total volume =1.4 lt
1-x+ 2x =1.4
x=.4
vopume of co=2×.4=.8 lt
volume of co2=1-.4 lt=.6 lt