MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
no. of molecules of co2 in 44mg of co2 is
1)6.023 * 10^23
2)6.023 * 10^22
3)6.023 * 10^21
4)6.023 * 10^20
7 months ago

Answers : (2)

Arun
22027 Points
							
First we get and calculate the atomic weight of carbon and oxygen
Carbon = 12 and oxygen=16
CO2=12+(16×2)
=12+32
=44u
44gm of CO2 has 6.02×10^23 molecules (Avogadro's number)
Therefore, 44g=(44×6.02×10^23)/44
=6.02×10^23 molecules
 
hence in 44mg = 6.02 x 10^21 molecules
 
7 months ago
Darsh patel
103 Points
							
The molecular mass of CO2 is 44 gm.Here given mass is 44mg .So no of moles of CO2 is (44*10^-3)gm/44 gm which gives us 10^-3 moles of CO2.Now as CO2 is a molecule itself.So no of molecules has formula (moles*Avogadro no.) Which gives us the no of molecules as[( 10^-3)*6.022*(10^23) molecules given that Avogadro no is equal to 6.022*10^23 .So the answer is 6.022*10^20 molecules going with option D.plz approve my answer.Best of luck for your preparation.
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details