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Mole concept chapter.Principle of atom conservation.I am getting a different answer compared to the book please solve it.
Molar mass of NX = 23+80 = 103So for 1 mole it is 103 gSo for 206 g it is 2 moles NX. Using stochiometry.....In 3rd rkn... For 8 moles NX it requires 1 mole M3X8... So for 2 moles we need 1/4 mole M3X8.NOW in second rkn. For 1/4 mole we need 3/4 moles of MX2.IN Rkn 1..for 3/4 mole MX2 we need 3/4 mole of M.1 mol M = 56gFor 3/4 moles we need 3/4 x 56 ie 42g M.So. Ans 42g M
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