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molar conductance of Bacl2, H2so4 ,and HCL at infinite dilutions are x1 ,x2 and x3 respect.. equivalent conductance of Baso4 at infinite dilution will be .please solve this immediately ,i’m totally confused on this .
HelloI have attached image for same.
dear NishantIt’s a pretty simple and basic concept oriented question.But no doubt does confuse people for a long time especially regarding the concept of equivalent and molar conductivity question. the answer may not be exactly apt but should help you enough to get the concept behind it. ANSWER ∂= lambda= equivalent conductance ( delta knot) ∂BaSO4 = ∂BaCl2 + ∂H2SO4 - ∂2HCl = x1 + x2 + – 2x3∂BaSO4 = 1000 * sp. conductance. solubility( in saturated sol.) x1 + x2 – 2x3 = 1000y/ solubility => solubility BaSO4 = 1000y N [ N= M/ z factor = M/2] x1+x2-2x3 = 1000y M x1+x2-2x3 BaSO4 ------> Ba 2+ + SO4 2- ksp (BaSO4)= [Ba 2+][SO4 2-] M^2 = 10^6 y^2 4(x1+x2-2x3)^2 RegardsArun (askIITias forum expert)
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