Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
molar conductance of Bacl2, H2so4 ,and HCL at infinite dilutions are x1 ,x2 and x3 respect.. equivalent conductance of Baso4 at infinite dilution will be .please solve this immediately ,i’m totally confused on this .
HelloI have attached image for same.
dear NishantIt’s a pretty simple and basic concept oriented question.But no doubt does confuse people for a long time especially regarding the concept of equivalent and molar conductivity question. the answer may not be exactly apt but should help you enough to get the concept behind it. ANSWER ∂= lambda= equivalent conductance ( delta knot) ∂BaSO4 = ∂BaCl2 + ∂H2SO4 - ∂2HCl = x1 + x2 + – 2x3∂BaSO4 = 1000 * sp. conductance. solubility( in saturated sol.) x1 + x2 – 2x3 = 1000y/ solubility => solubility BaSO4 = 1000y N [ N= M/ z factor = M/2] x1+x2-2x3 = 1000y M x1+x2-2x3 BaSO4 ------> Ba 2+ + SO4 2- ksp (BaSO4)= [Ba 2+][SO4 2-] M^2 = 10^6 y^2 4(x1+x2-2x3)^2 RegardsArun (askIITias forum expert)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -