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molar conductance of Bacl2, H2so4 ,and HCL  at infinite dilutions are x1 ,x2 and x3 respect.. equivalent conductance of Baso4 at infinite dilution will be .please solve this immediately ,i’m totally confused  on  this .
9 months ago

Answers : (2)

Ravleen Kaur
askIITians Faculty
983 Points
							Hello

I have attached image for same.560-1282_30-1.PNG
9 months ago
Arun
20341 Points
							
dear Nishant
It’s a pretty simple and basic concept oriented question.
But no doubt does confuse people for a long time especially regarding the concept of equivalent and molar conductivity question.
 
the answer may not be exactly apt but should help you enough to get the concept behind it.
 
ANSWER
 
∂= lambda= equivalent conductance ( delta knot)
 
∂BaSO4 = ∂BaCl2 + ∂H2SO4 - ∂2HCl
             = x1 + x2 + – 2x3
∂BaSO4 = 1000 * sp. conductance.
               solubility( in saturated sol.)
 
x1 + x2 – 2x3 = 1000y/ solubility
 
=> solubility BaSO4 = 1000y N                [ N= M/ z factor = M/2]
                                x1+x2-2x3
 
                              = 1000y M
                                 x1+x2-2x3
 
       BaSO4 ------> Ba 2+ + SO4 2- 
ksp (BaSO4)= [Ba 2+][SO4 2-] M^2
                   = 10^6 y^2
                   4(x1+x2-2x3)^2
 
 
Regards
Arun (askIITias forum expert)
9 months ago
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