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Mixture X = 0.02 mole of [Co(NH3)5 SO4] Br and 0.02 mole of [Co(NH3)5 Br]SO4 was prepared in 2 L solution. 1 L of mixture X + excess of AgNO3 solution →Y 1 L of mixture X + excess of BaCI2 solution →Z Number of moles of Y and Z are a. 0.01, 0.01 b. 0.02, 0.01 c. 0.01, 0.02 d. 0.02, 0.02

Mixture X = 0.02 mole of [Co(NH3)5 SO4] Br and 0.02 mole of [Co(NH3)5 Br]SO4 was prepared in 2 L solution.
1 L of mixture X + excess of AgNO3 solution →Y
1 L of mixture X + excess of BaCI2 solution →Z
Number of moles of Y and Z are
a. 0.01, 0.01
b. 0.02, 0.01
c. 0.01, 0.02
d. 0.02, 0.02

Grade:10

3 Answers

Navjyot Kalra
askIITians Faculty 654 Points
9 years ago
Sol. 1.0 L of mixture X contain 0.01 mole of each [(Co(NH3)5 SO4)]Br an [Co(NH3)5 Br]SO4. Also, with AgNO3, only [(Co(NH3)5 SO4)]Br reacts to give AgBr precipitate as [Co(NH3)5 SO4]Br + AgNO3→ [Co(NH3)5 SO4]NO3 + AgBr 1.0 mol 1.0 mol excess
Mradul singh
13 Points
5 years ago
(A) should be answer as [(Co(NH3)5 SO4)]Br  reacts with Agno3 to give AgBr as precipitate.
so 1 mole of  [(Co(NH3)5 SO4)]Br react with 1 mole of agno3 to give 1 mole Y
same follows for ii case
 
ankit singh
askIITians Faculty 614 Points
3 years ago
) should be answer as [(Co(NH3)5 SO4)]Br  reacts with Agno3 to give AgBr as precipitate.
so 1 mole of  [(Co(NH3)5 SO4)]Br react with 1 mole of agno3 to give 1 mole Y
same follows for ii case

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