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maximum value (n+l+m) for an unpaired electron in excited state of chlorine is
Atomic no. of chlorine = 17 Ground state configuration = 1s2 2s2 2p6 3s2 3p5 ,in excited state the configuration become3s1 3p6, thus,For unpaired electron value of n = 3 ,l = 0 ,m = 0 so n+l+m = 3+0+0 = 3Thanks & regardsAarti guptaaskiitians faculty
but the answer is 7 not 3 @aarti
The electron from P orbital of third shell will enter d orbital of the third shell so maximum value of n,l,m will be 2,3,3 resp. So n+L+m = 3+2+2=7
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