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Maximum efficiency of cationic hydrolysis will be shown by- 1.Al+3 2.Ga+3 3.Tl+3

Maximum efficiency of cationic hydrolysis will be shown by-
1.Al+3    2.Ga+3   3.Tl+3

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1 Answers

Arun
25750 Points
5 years ago
Extent of hydrolysis depends on the (charge ÷ radius) ratio. So greater the charge and lesser the size , greater will be the hydrolysis.
Since all of them have same charge of +3, we will decide by size .
Since size increases down the group, Al has smallest size.
So Al3+ has greatest efficiency of hydrolysis.

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